I worked this problem earlier for nitrate. Mg is done the same way. It's a little more complicated for Ag because AgCl is a ppt. The total volume is 95 + 20 = 115 mL.
After mixing, (AgNO3) = 0.8 x (95/115) = about 0.66
(MgCl2) = 0.2 x (20/115) = about 0.035 but that is not exact and you need to determine it more accurately (as well as all of the calculations that follow).
..........AgCl==> Ag^+ + Cl^-
I.........solid...0.....2*0.035
C.........solid...x......x
E.........solid...x.....0.070+x
Ksp = you look it up but approx 1E-10 = (x)(0.07+x) = about 1E-10
Solve for x = (Ag^+)
A 20.00 mL of 0.200mol/L magnesium chloride solution is added to a 95.00 mL of 0.800 silver (I) nitrate solution,Determine the concetration of the silver ions at the end of the reaction and the magnesium ions. and a precipitate is formed.
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