A 10.-newton force is required to hold a
stretched spring 0.20 meter from its rest position. What is the potential energy stored in the
stretched spring?
5 answers
I believe the answer is 1/2kx^2=Fd=10N(0.2m)=2J. Hopefully someone checks this.
It's actually 1J. You forgot to divide by one! Thank you!
Double check that. Are you sure that it is 1J?
It's definitly 1J
Guys it is 1 J
1 answer