a. d = (120N/265N) * 0.15m
b. (F/265) * 0.15 = 0.30
0.15F = 79.5
F = 530 N.
Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring.
A force of 265 newtons stretches a spring 0.15 meter (see figure).
(a) How far will a force of 120 newtons stretch the spring? (Round your answer to two decimal places.)
:m
(b) What force is required to stretch the spring 0.3 meter? (Round your answer to two decimal places.)
:N
1 answer