A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.) (1 point)

Question

• 1,280 - 30h = 0
• 1,280 + 30h = 0
• 10 - 30h = 0
• 30h = 10

Answer 1

To find how long the water in the cooler will last, we start by noting that the cooler has 1,280 ounces and that water is being removed at a rate of 30 ounces per hour. We want to find the time \( h \) in hours when the cooler will be empty (meaning the amount of water left will be 0).

We can model this situation with an equation based on the amount of water remaining:

1. The initial amount of water is 1,280 ounces.
2. After \( h \) hours, the amount of water removed is \( 30h \) ounces.
3. Therefore, the amount of water left in the cooler after \( h \) hours is given by the equation:

\[ 1,280 - 30h = 0 \]

This equation states that after \( h \) hours, the remaining water will be zero. So, the correct equation is:

1,280 - 30h = 0