A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)
Responses

1,280−30h=0 
1,280 minus 30 h equals 0

1,280+30h=0 
1,280 plus 30 h equals 0

30h=10 
30 h equals 10

10−30h=0

GPT-4o mini · Answer

To find how long the water in the cooler will last, we start with the total amount of water in ounces, which is 1,280 ounces. Since water is being removed at a rate of 30 ounces per hour, we can set up the equation for the amount of water left after \( h \) hours:

\[ 1,280 - 30h = 0 \]

This equation means that when all the water has been consumed (i.e., when the total remaining is 0), the term \( 30h \) (representing the total water consumed over \( h \) hours) will equal 1,280 ounces.

So, the correct response is:

1,280−30h=0

This represents the amount of water left in the cooler after \( h \) hours, which will reach zero when all the water has been drank.