A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

1,280+30h=0
1,280 plus 30 h equals 0
30h=10
30 h equals 10
1,280−30h=0
1,280 minus 30 h equals 0
10−30h=0
10 minus 30 h equals 0

Answer 1

To determine how long the water in the cooler will last, we can set up an equation based on the information given in the problem.

Starting with the total amount of water in the cooler, which is 1,280 ounces, we note that every hour, 30 ounces are consumed. We want to find the time \( h \) (in hours) when the amount of water remaining becomes zero.

The equation that represents this situation is:

\[ 1,280 - 30h = 0 \]

This equation reflects that we start with 1,280 ounces and subtract 30 ounces for each hour \( h \) until no water is left (which is represented by the equation being equal to 0).

So, the correct response is:

1,280−30h=0