Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)
Responses

30h=10
30 h equals 10

1,280+30h=0
1,280 plus 30 h equals 0

1,280−30h=0
1,280 minus 30 h equals 0

10−30h=0

Answer 1

To find out how long the water in the cooler will last, we can set up an equation based on the amount of water being consumed.

1. The total amount of water in the cooler is 1,280 ounces.
2. The office workers consume 30 ounces of water per hour.

Let \( h \) represent the number of hours the water lasts. After \( h \) hours, the amount of water remaining can be represented as:

\[
1,280 - 30h = 0
\]

This equation states that after \( h \) hours of consumption, the water in the cooler will be depleted to 0 ounces.

Thus, the correct equation is:

\[
\boxed{1,280 - 30h = 0}
\]