Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.) (1 point) 1,280-30h=0 30h=10 10-30h=0 1,280+30h=0

Answer 1

To determine how long the water in the cooler will last, we can set up an equation based on the amount of water being removed over time.

Given that the cooler starts with 1,280 ounces of water and each hour, 30 ounces are removed, we want to find \(h\) (the number of hours) when the water will run out.

The correct equation is:

\[ 1,280 - 30h = 0 \]

This equation states that the initial amount of water (1,280 ounces) minus the amount of water removed over \(h\) hours (30 ounces per hour) will equal zero when the water runs out.

So, the answer is:

**1,280 - 30h = 0**