A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

10−30h=0
10 minus 30 h equals 0

1,280−30h=0
1,280 minus 30 h equals 0

1,280+30h=0
1,280 plus 30 h equals 0

30h=10

Answer 1

To determine how long the water in the cooler will last, we can start with the total amount of water in ounces and set up an equation based on the amount of water being consumed per hour.

1. We know the total amount of water is 10 gallons, which is equivalent to 1,280 ounces.
2. Each hour, 30 ounces of water are consumed by the office workers.

We want to find the number of hours (h) until the water runs out, which is represented when the amount of water reaches 0. Therefore, we can write the equation:

\[ 1,280 - 30h = 0 \]

This equation shows that we start with 1,280 ounces and lose 30 ounces for each hour (h) until there is no water left.

So the correct response is:

1,280−30h=0
(1,280 minus 30 h equals 0)