A 10-g bullet moving 1000 m/s strikes and passes through a 2.0-kg block initially at rest, as shown. The bullet emerges from the block with a speed of 400 m/s. To what maximum height will the block rise above its initial position?

Answer 1

Pi=Pf
m1v1i+m2v2i=m1v1f+m2v2f
0.01x1000+2x0=0.01x400+2xv2f
v2f=3m2^-1

vf^2-vi^2=2as
s=h
a=g=9.8
therefore,
0-3^2=2(-9.8)h
h=0.46m