A 35.0-g bullet moving at 475 m/s strikes a 2.5-kg wooden block. The bullet passes through the block, leaving at 275 m/s. The block was at rest when it was hit. How fast is it moving when the bullet leaves?

Answer 1

.035 * 475 = initial momentum

.035*275 + 2.5 * v = final momentum

initial momentum = final momentum. Solve for v