A 1.6 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.6 . The bubble rises slowly enough that the air inside remains at the same constant temperature as the water. What is the volume of the bubble as it reaches the surface?

4 answers

pV=nRT (bottom of ocean)
pV=nRT (top of ocean)

n,R,T are all constants so those cancel out
pV(bottom)= pV(top)

pV(bottom)/p(top)=V(top)

1.6*1.6/1.0=V
V=2.56cm3
Since gauge pressure=p-p_0, you must add p_0 back to the gauge pressure and then multiply by the volume and then divide by atmospheric pressure.
My physics teacher says that 1 atm is added.
(1.6+ 1.0)*1.6)/1.0