A 1.6 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.6 . The bubble rises slowly enough that the air inside remains at the same constant temperature as the water. What is the volume of the bubble as it reaches the surface?

Answer 1

pV=nRT (bottom of ocean)
pV=nRT (top of ocean)

n,R,T are all constants so those cancel out
pV(bottom)= pV(top)

pV(bottom)/p(top)=V(top)

1.6*1.6/1.0=V
V=2.56cm3

Answer 2

Since gauge pressure=p-p_0, you must add p_0 back to the gauge pressure and then multiply by the volume and then divide by atmospheric pressure.

Answer 3

My physics teacher says that 1 atm is added.

Answer 4

(1.6+ 1.0)*1.6)/1.0