Asked by Aj

A 1.4-kg block of ice is at a temperature of -10∘C. If 6200 J of thermal energy is added to the ice, what is its final temperature?
Answered by R_scott
from google ...
... the specific heat of ice is 2.04kJ/kg/K and the latent heat of fusion is 335kJ/kg

6.2 kJ is not enough to heat the block to the melting point

specific heat * mass * Δt = 6.2 kJ
... solve for Δt
Answered by nick
so I just solve 2.04 * 335 * = 6.2? im confused
Answered by oobleck
correct --
2.04 * 335 * Δt = 6.2
solve for Δt and then add that to the -10°C starting point (since °C are the same as °K)

-- look at the units.
J/(kg * °K) * kg * °K = J
Answered by R_scott
the mass is not 335 ... it is 1.4
Answered by nick
yea isn't the mass 1400?
Answered by R_scott
the specific heat number is in kg ... not grams
Answered by oobleck
oops my bad - dunno how I scrambled things up.
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