Asked by out of time
Q: A 5.0 kg block is placed on top of a 10. kg block.(DIAGRAM : ww w.ux1.eiu.edu/~cfadd/1350/Hmwk/Ch05/Images/P5.74.g i f) A horizontal force of 45 N is applied to the 10. kg block and the 5.0 kg block is tied to the wall. The coefficient of friction between the moving surfaces is 0.20.
Determine the tension in the string that ties the 5.0 kg block to the wall
so fnet = =Ft+uma
OR is it Fnet = -Ft+umg
reall im asking since the 5kg block is on top and the 10kg block get a Force applied of 45N would we use ma or mg???
Determine the tension in the string that ties the 5.0 kg block to the wall
so fnet = =Ft+uma
OR is it Fnet = -Ft+umg
reall im asking since the 5kg block is on top and the 10kg block get a Force applied of 45N would we use ma or mg???
Answers
Answered by
bobpursley
Ft=force of friction on top-forceoffriction bottom
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.