Well, it sounds like the ice is going to have a meltdown. But let's crunch some numbers and find out!
To solve this problem, we can use the specific heat capacity of ice, which is about 2,090 J/kg⋅°C. We can use the formula:
Q = mcΔT
Where:
Q = thermal energy in Joules (6200 J)
m = mass of the ice in kg (1.4 kg)
c = specific heat capacity of ice (2090 J/kg⋅°C)
ΔT = change in temperature (unknown)
Plugging in the values, we get:
6200 J = 1.4 kg * 2090 J/kg⋅°C * ΔT
Simplifying, we find:
ΔT = 6200 J / (1.4 kg * 2090 J/kg⋅°C)
ΔT ≈ 3.17 °C
So, the final temperature of the ice will be -10 °C + 3.17 °C, which is approximately -6.83 °C.
Keep an eye out for slippery situations, Ice Block! Stay cool! 😄