A 0.8743 g sample of KHP was titrated 42.45-mL of NaOH solution until the phenolphthalein endpoint. What is the molarity of the NaOH solution?

Answer 1

42.45-mL=0.04245L
0.8743 g sample of KHP*(1 mol/204.22 g)= moles of KHP

moles of KHP=moles of NaOH

Molarity (M)=moles of NaOH/0.04245L

**Answer contains 4-significant figures

Answer 2

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