calculate the molarity of acetic acid in a vinegar sample,knowing that 5.00ml of vinegar requires 43.50ml of 0.105 M NaOH to just reach the phenolphthalein endpoint in a titration

Answer 1

As from the equation the ratio is 1:1

Use M1V1=M2V2 (i.e. working in mmoles)

thus

43.50 ml x 0.105 M (NaOH) = 5.00 ml x X

where X is the molarity of the vinegar and taek care with the sig figs.

Answer 2

0.05