Assuming the density of vinegar is 1.0 g/mL ' what is the molarity of vinegar? (use the percent by mass of acetic acid to vinegar which is 5%.) The molar mass of acetic acid is 60.05 g/mol?

Answer 1

%w/w = grams solute/100 g solution.
%w/w = 5 grams CH3COOH/100 mL soln.
moles CH3COOH = 5/60.05 = ?? moles/100 mL.
Then M = moles/L soln.

Answer 2

Household vinegar is aquous, 5% acetic acid HC2H3O2 solution by mass. The molarity is: 5% = 5g
1mol HC2H3O2 = 60.05g HC2H3O2
5g/60.05g = 0.08326394671 mol
therefore the molarity is 0.08326394671 mol/0.01L = 0.84mol/L