A 0.22 calibre rifle shoots a bullet of mass 1.8 g with a muzzle velocity of 500 m/s. If the barrel is 25 cm long, what is the average force exerted on the bullet while it is in the barrel?

Answer 1

force * distance = work
so work done = .025 F
which we assume is Ke of bullet
(1/2) m v^2 = .025 F
(1/2) (.0018) (500)^2 = .025 F