A.)p = m * v
With the bullet travelling at v =413 m/s with a mass of 0.0045 kg:
p(bullet) = 0.0045 * 413
p(bullet) = 1. 8585 N.s
answer: 1.8585 N.s
B.)The recoil velocity of the rifle, this is a conservation of momentum problem. So,
p(initial) = p(final)
In other words, the products of all masses with their velocities should be equal before and after the interaction. This becomes:
m1*u1 + m2*u2 = m1*v1 + m2*v2 :
(1.884)(0) + (0.0045)(0) = (1.84) v1 + (0.0045)(413)
0 = 1.84 * v1 + 1.8585
-1.8585 = 1.84 * v1
v1 = -1.8585 / 1.84
v1 = -1.010054348 m/s
answer: 1.010054348 m/s
A rifle with a mass of 1.84 kg fires a bullet with a mass of 4.5 g (0.0045 kg). The bullet moves with a muzzle velocity of 413 m/s after the rifle is fired.
(a) What is the momentum of the bullet after the rifle is fired?
(b) If external forces acting on the rifle can be ignored, what is the recoil velocity of the rifle?
1 answer
1 answer