F=Δp/Δt =m(v₂-v₁)/Δt
v₂ =0
Δt= m v₂/F=(-0.2•25.2)/(- 387)= 0.013 s
a= - v₁/Δt=-25.2/0.013 = - 1938.5 m/s²
s=- v₁²/2a=-25.2²/2•(-1938.5)=0.16 m
A 0.20 kg baseball moving at +25.20 m/s is slowed to a stop by a catcher who exerts a constant force of -387 N.
A)How long does it take this force to stop the ball?
B)How far does the ball travel before stopping?
1 answer
1 answer