A 0.17 kg baseball moving at +20.80 m/s is slowed to a stop by a catcher who exerts a constant force of -376 N.

How long does it take this force to stop the ball?
How far does the ball travel before stopping?

1 answer

Force*Time = Initial Momentum = M*V
Time = (0.17)*(20.8)/376 = 9.4*10^-3 s

(Initial velocity)/2 * Time
= Stopping Distance

= 10.40*9.4*10^-3 = 0.0978 m
= 9.7 cm