force * time = change in momentum
360 * t = .18*26
solve for t
a = change in velocity/time
= -26/t
Vi = 26
d = Vi t + (1/2)a t^2
d = 26 t - (1/2)(26)t
d = 13 t
A 0.18 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a constant force of −360 N.
a) How long does it take this force to stop the ball?
b) How far does the ball travel before stop- ping?
1 answer