A 0.077 kg arrow is fired horizontally. The bowstring exerts an average force of 80 N on the arrow over a distance of 0.80 m. With what speed does the arrow leave the bow?

Answer 1

work done on arrow = force* distance = 80*.8 = 64 Joules
that is now kinetic energy
(1/2) m v^2 = 64
I think you can solve for v

Answer 2

how do you solve for v ?

Answer 3

V = sqroot of (2 x 64) / m