A 0.069-kg arrow is fired horizontally. The bowstring exerts an average force of 65 N on the arrow over a distance of 0.95 m. With what speed does the arrow leave the bow?

Answer 1

Work done on arrow = Kinetic energy
65*0.95 = (M/2)V^2 = 0.0345 V^2

Solve for V, in m/s.

I get 42.3 m/s