Do you even need to know the mass of the ball? I don't know, but I think that I need to determine the initial velocity in the y-direction, first:
Vf^2=Vi^2-2gd
where:
d=23.2m
Vf=0m/s
g=9.8m/s^2
Solve for Vi:
Vi=Sqrt(2*9.8m/s^2*23.2m)
Vi=21.32m/s
Conservation of energy tell me that
MEi=MEf
mgh+1/2mv^2=mgh+1/2mv^2
Masses are on both sides of my equation, so they cancel out.
gh+1/2v^2=gh=1/2v^2
Maybe I don't need to know the mass of the ball.
Solve for v:
where
For the left side of the equation
g=9.8m/s^2
h=0m
and
v=54m/s
For the right side of the equation
g=9.8m/s
h=23.2-6m=17.2m
and
v=??
Solve for the v:
0J+1/2(21.32m/s)^2=(9.8m/s)*(17.2m)+1/2v^2
227.32J=168.56J+1/2v^2
227.32J-168.56J=1/2v^2
Sqrt*[2*(1458J-168.56J)]=v
v=10.84m/s
A 0.047 kg golf ball is driven from the tee with an initial speed of 54 m/s and rises to a height of 23.2 m.
What is its speed when it is 6.0 m below its highest point?
3 answers
For the left side of the equation
g=9.8m/s^2
h=0m
and
v=21.32m/s **** Correction
For the right side of the equation
g=9.8m/s
h=23.2-6m=17.2m
and
v=??
Solve for the v:
0J+1/2(21.32m/s)^2=(9.8m/s)*(17.2m)+1/2v^2
227.32J=168.56J+1/2v^2
227.32J-168.56J=1/2v^2
Sqrt*[2*(1458J-168.56J)]=v
v=10.84m/s
g=9.8m/s^2
h=0m
and
v=21.32m/s **** Correction
For the right side of the equation
g=9.8m/s
h=23.2-6m=17.2m
and
v=??
Solve for the v:
0J+1/2(21.32m/s)^2=(9.8m/s)*(17.2m)+1/2v^2
227.32J=168.56J+1/2v^2
227.32J-168.56J=1/2v^2
Sqrt*[2*(1458J-168.56J)]=v
v=10.84m/s
This is the whole thing corrected; ignore the previous two post.
Do you even need to know the mass of the ball? I don't know, but I think that I need to determine the initial velocity in the y-direction, first:
Vf^2=Vi^2-2gd
where:
d=23.2m
Vf=0m/s
g=9.8m/s^2
Solve for Vi:
Vi=Sqrt(2*9.8m/s^2*23.2m)
Vi=21.32m/s
Conservation of energy tells me that
Initial Mechanical Energy=Final Mechanical Energy
mgh+1/2mv^2=mgh+1/2mv^2
Masses are on both sides of my equation, so they cancel out, and I am left with the following:
gh+1/2v^2=gh +1/2v^2
I was correct: I don't need to know the mass of the ball.
Solve for v:
where
For the left side of the equation,
g=9.8m/s^2
h=0m
and
v=21.32m/s
And for the right side of the equation,
g=9.8m/s
h=23.2m-6m=17.2m
and
v=??
Solve for the v:
(9.8m/s^2)*(0m)+1/2(21.32m/s)^2=(9.8m/s)*(17.2m)+1/2v^2
0J + 227.32J=168.56J+1/2v^2
227.32J-168.56J=1/2v^2
Sqrt*[2*(1458J-168.56J)]=v
v=10.84m/s
Do you even need to know the mass of the ball? I don't know, but I think that I need to determine the initial velocity in the y-direction, first:
Vf^2=Vi^2-2gd
where:
d=23.2m
Vf=0m/s
g=9.8m/s^2
Solve for Vi:
Vi=Sqrt(2*9.8m/s^2*23.2m)
Vi=21.32m/s
Conservation of energy tells me that
Initial Mechanical Energy=Final Mechanical Energy
mgh+1/2mv^2=mgh+1/2mv^2
Masses are on both sides of my equation, so they cancel out, and I am left with the following:
gh+1/2v^2=gh +1/2v^2
I was correct: I don't need to know the mass of the ball.
Solve for v:
where
For the left side of the equation,
g=9.8m/s^2
h=0m
and
v=21.32m/s
And for the right side of the equation,
g=9.8m/s
h=23.2m-6m=17.2m
and
v=??
Solve for the v:
(9.8m/s^2)*(0m)+1/2(21.32m/s)^2=(9.8m/s)*(17.2m)+1/2v^2
0J + 227.32J=168.56J+1/2v^2
227.32J-168.56J=1/2v^2
Sqrt*[2*(1458J-168.56J)]=v
v=10.84m/s
1 answer