A 46.7-g golf ball is driven from the tee with an initial speed of 55.5 m/s and rises to a height of 25.9 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 5.85 m below its highest point?

Answer 1

a. Ek = 0.5m*V^2 = 0.5*0.0467*0^2 = 0.
Note: The velocity is 0 at the max. ht.

b. V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*(25.9-5.85) = 391
V = 19.8 m/s.