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In the process of electrolysis, electrical power is used to separate water into oxygen and hydrogen molecules via the reaction:...Asked by Chris
In the process of electrolysis, electrical power is used to separate water into oxygen and hydrogen molecules via the reaction:
H2O --> H2 + ½O2
This is very much like running a hydrogen fuel cell in reverse. We assume that only the activation potential for the hydrogen reaction is non-negligible. All other potentials are negligible. Hence the relevant parameters are :
PO2 :1 atm
PH2: 1 atm
Temp: 350K
j0(H2): 0.1A/cm2
α(H2): 0.50
1. What is the current density in A/cm2 at a voltage of 1.5 V?
2. What area of the cell, in cm2, do we need in order to get a rate of H2 production of 1 mol/sec?
H2O --> H2 + ½O2
This is very much like running a hydrogen fuel cell in reverse. We assume that only the activation potential for the hydrogen reaction is non-negligible. All other potentials are negligible. Hence the relevant parameters are :
PO2 :1 atm
PH2: 1 atm
Temp: 350K
j0(H2): 0.1A/cm2
α(H2): 0.50
1. What is the current density in A/cm2 at a voltage of 1.5 V?
2. What area of the cell, in cm2, do we need in order to get a rate of H2 production of 1 mol/sec?
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