Asked by Sanaa
consider the electrolysis of molten AlCl3 what must the current be in amps if you need to obtain 25.0 grams of aluminum in 5.00 min
Answers
Answered by
DrBob222
It takes 96,485 coulombs to deposit 1 equivalent weight of Al (27/3 = 9 grams).
Therefore, it will take
96,485 x (25/9) to deposit 25.0 grams = ??
The amperes x sec = coulombs.
You know sec (convert 5 min to seconds) and coulombs, calculate amperes.
Therefore, it will take
96,485 x (25/9) to deposit 25.0 grams = ??
The amperes x sec = coulombs.
You know sec (convert 5 min to seconds) and coulombs, calculate amperes.
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