Asked by chyanne

A force of 50.0N is used to stretch an elastic so that it had 40.0 J of elastic potential energy. Through what distance was the elastic stretched?

F= 50.0N
??
how do i solve.. ugh!
Answered by Emily
Plz post the formula I forgot what it is... if you have one.
Answered by Anonymous
W = (F)(d)

Substitute the formula and isolate for "d"

40J = 50N x d

40J/50N = d
0.8m = d
Answered by chyanne
thanks!
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