Asked by Jessie
1. Two forces are applied to a box on a frictionless surface. One force is 40 N [S]. The second force is 70 N [N30ºW]. What is the overall net force?
a) 40.6 N [S59.5ºE]
b) 110 N
c) 40.6 N [N59.5ºW]
d) 40.6 N [S30.5ºW]
2. When drawing free body diagrapms, it is important to:
a) draw your diagram to scale
b) add force vectors tip-to-tail
c) represent the magnitude force using the length of the arrows
d) all of the above
a) 40.6 N [S59.5ºE]
b) 110 N
c) 40.6 N [N59.5ºW]
d) 40.6 N [S30.5ºW]
2. When drawing free body diagrapms, it is important to:
a) draw your diagram to scale
b) add force vectors tip-to-tail
c) represent the magnitude force using the length of the arrows
d) all of the above
Answers
Answered by
bobpursley
a. one force is south, the other is slightly north of west. Well, the resultant definitely is towards the west, which eliminates a, b.
So what is the N component of the second force Northcomponent=70sin30 = 35Newtons, but there is a 40N S force, so the net force is S of W
b. silly question,when drawing one never has it to scale, only approximately so. tip to tail is important.
what about magnitude? well it helps, but we always just sketch.
So b is the best answer, but I can see a poorly prepared teacher ready to argue. Don't argue with the teacher, it is a losing battle, usually, in Physics classes.
So what is the N component of the second force Northcomponent=70sin30 = 35Newtons, but there is a 40N S force, so the net force is S of W
b. silly question,when drawing one never has it to scale, only approximately so. tip to tail is important.
what about magnitude? well it helps, but we always just sketch.
So b is the best answer, but I can see a poorly prepared teacher ready to argue. Don't argue with the teacher, it is a losing battle, usually, in Physics classes.
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