Asked by Dani

Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 402 N and F2 = 364 N. (Assume up and to the right as positive directions.)(F1 is 10degrees and F2 is 30degrees)
(a) What is the resultant of these two forces?
magnitude
direction

(b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction.
Answered by Henry
F1 = 402N @ 10 Deg.
F2 = 364N @ 30 Deg.

a. X = hor. = 402cos10 + 364cos30,
X = 395.9 + 315.2 = 711.1N.

Y = ver. = 402sin10 + 364sin30,
Y = 69.8 + 182 = 251.8N.

tanA = Y/X = 251.8 / 711.1 = 0.3541,
A = 19.5 Deg. = Direction.

M = X/cosA = 711.1 / cos19.5 = 754.4N =
Magnitude.

b. F = ma,
a = F/m = 754.4 / 3000 = 0.25m/s^2



Answered by Anonymous
remember if the degrees is negative then subtract it from 360

example:
F1 @ -10 deg
F2 @ 30 deg

F1 is actually @ 350 deg
F2 is still 30 deg
Answered by Miguel
You have to remember that there's no force being created on the x axis, the answer below must've been wrong because of that.
Answered by Isaac
For A use)
Magnitude = (X^2+Y^2)^1/2
tan^-1(theta) = X/Y

For B use)
a = Magnitude/mass
Answered by Isaac
theta = tan^1(X/Y)
Answered by Dr_drek
After I solve for the angle by using tangent, is that angle the direction? or am I supposed to subtract it from something (like 90)?
Answered by Dr. Michael Morbius
morbius hates physics urrraaaaagh IM GONNA MORB ON ISAAC NEWTON
There are no AI answers yet. The ability to request AI answers is coming soon!