Asked by john
In a gas mixture of He, Ne, and Ar with a total pressure of 8.40 atm, the mole fraction of Ar is ________ if the partial pressures of He and Ne are 1.50 and 2.00 atm respectively.
pHe = 1.50 atm.
pNe = 2.00 atm.
pAr = 8.40 atm - 1.50 - 2.00 = ??
mole fraction Ar = pAr/total p.
pHe = 1.50 atm.
pNe = 2.00 atm.
pAr = 8.40 atm - 1.50 - 2.00 = ??
mole fraction Ar = pAr/total p.