Asked by Janjan
A mixture containing only BaO and CaO weighs 1.5 g. The oxides are converted to the corresponding mixed sulfates, which weigh 3.0 g. Calculate the percent Ba and Ca in the original mixture.
Answers
Answered by
DrBob222
am = atoomic mass
mm = molar mass
Let X = mass BaO in the sample
and Y = mass CaO in the sample
So % Ba = [X*(am Ba/mm BaO)/1.5]*100 = ?
%Ca = [Y*(am Ca/mm CaO/1.5)]*100 = ?
The remainder of the problem is to determine the X and Y and you do that by setting up two equations and solving them simultaneously.
eqn1 is X + Y = 1.5 g
eqn2 is (mmBaSO4/mmBaO)X + (mmCaSO4/mmCaO)Y = 3.0 g
Solve eqn 1 and eqn2 simultaneously and plug X and Y into those % equations at top to obtain %Ba and %Ca.
mm = molar mass
Let X = mass BaO in the sample
and Y = mass CaO in the sample
So % Ba = [X*(am Ba/mm BaO)/1.5]*100 = ?
%Ca = [Y*(am Ca/mm CaO/1.5)]*100 = ?
The remainder of the problem is to determine the X and Y and you do that by setting up two equations and solving them simultaneously.
eqn1 is X + Y = 1.5 g
eqn2 is (mmBaSO4/mmBaO)X + (mmCaSO4/mmCaO)Y = 3.0 g
Solve eqn 1 and eqn2 simultaneously and plug X and Y into those % equations at top to obtain %Ba and %Ca.
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