Question

I am trying to find the inverse of these functions. Can someone please check my answers and tell me how to do number 2?

1. y=7^x
y=log base 7 x

2. y=log base 1/2 x

3. y=2^(x)-3
y=2^(x+3)

4.y=6+log x

Answer 1

#1. ok
#2. y = (1/2)^x = 2^-x
#3. log₂(x+3)
#4. e^(x-6)
if base 10, 10^(x-6)

Answer 2

Thank you

Answer 3

1 ok

2. b^logb(x) = x
x = log.5 y
.5^x = .5^log.5(y) = y
so
y = .5^x

3. x = 2^y - 3
x+3 = 2^y
log2 (x+3) = y

4. x = 6 + log y log base e or 10 ???
I will assume 10
x-6 = log y
10^(x-6) = y
y = 10^x/10^6