Asked by Gabie
Find inverse f(x)=2/-2x-5
Answers
Answered by
oobleck
start with y = 2/(-2x-5)
and switch variables, then solve for y again.
x = 2/(-2y-5)
2y+5 = -2/x
2y = -2/x - 5
y = -1/x - 5/2 = -(5x+2)/(2x)
so that means that
f<sup><sup>-1</sup></sup>(x) = -(5x+2)/(2x)
you should always check your results, to make sure that
f<sup><sup>-1</sup></sup>(f(x)) = f(f<sup><sup>-1</sup></sup>(x)) = x
and switch variables, then solve for y again.
x = 2/(-2y-5)
2y+5 = -2/x
2y = -2/x - 5
y = -1/x - 5/2 = -(5x+2)/(2x)
so that means that
f<sup><sup>-1</sup></sup>(x) = -(5x+2)/(2x)
you should always check your results, to make sure that
f<sup><sup>-1</sup></sup>(f(x)) = f(f<sup><sup>-1</sup></sup>(x)) = x
Answered by
mathhelper
I will assume you meant:
f(x)=2/(-2x-5)
let y = 2/(-2x-5)
step1: interchange the x and y variables
---> x = 2/(-2y-5)
step2: solve this new equation for y
2 = - 2xy - 5x
2xy = -2 - 5x
y = (-2 - 5x)/(2x)
f ^-1 (x) = (-2 - 5x)/(2x)
f(x)=2/(-2x-5)
let y = 2/(-2x-5)
step1: interchange the x and y variables
---> x = 2/(-2y-5)
step2: solve this new equation for y
2 = - 2xy - 5x
2xy = -2 - 5x
y = (-2 - 5x)/(2x)
f ^-1 (x) = (-2 - 5x)/(2x)
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