Asked by Megan
Determine the molar mass of a compound and its molecular formula if a solution of 1.00 g of the unknown is dissolved in 50 grams of cyclohexane. Cyclohexane freezes at 6.02 oC. The normal freezing point of cyclohexane is 6.50 oC and its kf value is 20.2 oC/m. The percent composition of the unknown is 85.71% C and 14.29% H
Answers
Answered by
DrBob222
delta T = Kf*m
Substitute and solve for m = molality.
m = mols/kg solvent
You know m and kg solvent, solve for mols.
mols = g/molar mass.
You know mols and g, solve for molar mass. I obtained in the neighborhood of 842 as the approximate molar mass.
For the compound with 85.71%C and 14.29%H, convert to mols.
85.71/12 = about 7.14 mols C
14.29g/1 = 14.29 mols H which is a ratio of CH2. That's the empirical formula with an empirical mass of 14
842/14 = about 60.2 which rounds to 60 so the molecular formula is (CH2)<sub>60</sub> or C60H120 with a more accurate molar mass of (60*12 + 120*1) = ?
Substitute and solve for m = molality.
m = mols/kg solvent
You know m and kg solvent, solve for mols.
mols = g/molar mass.
You know mols and g, solve for molar mass. I obtained in the neighborhood of 842 as the approximate molar mass.
For the compound with 85.71%C and 14.29%H, convert to mols.
85.71/12 = about 7.14 mols C
14.29g/1 = 14.29 mols H which is a ratio of CH2. That's the empirical formula with an empirical mass of 14
842/14 = about 60.2 which rounds to 60 so the molecular formula is (CH2)<sub>60</sub> or C60H120 with a more accurate molar mass of (60*12 + 120*1) = ?
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