Asked by Steph
Determine the molar mass of the following:
0.94g of a gas that occupies 500L at 0 degrees celcius and 1.00 (STP).
I keep getting 32g/mol
0.94g of a gas that occupies 500L at 0 degrees celcius and 1.00 (STP).
I keep getting 32g/mol
Answers
Answered by
bobpursley
PV=nRT
n=mass/MM =PV/RT
MM=mass*RT/PV=.94*
so the volume for one mole at STP is 22.4 liters, so here you must have 500/22.4 moles which is almost 23 moles.
well, if .94 grams is 23 moles, this must be the a gas made up of quarks, or unknown matter much lighter than hydrogen. I wonder if you meant .5L?
If so, then .5/22.4 moles=about .022 moles, so .94g/.022moles equals about a molecular mass of about 42.7 grams.
Work this out exactly. But I wonder what the 500L volume should be, it is not 500L
n=mass/MM =PV/RT
MM=mass*RT/PV=.94*
so the volume for one mole at STP is 22.4 liters, so here you must have 500/22.4 moles which is almost 23 moles.
well, if .94 grams is 23 moles, this must be the a gas made up of quarks, or unknown matter much lighter than hydrogen. I wonder if you meant .5L?
If so, then .5/22.4 moles=about .022 moles, so .94g/.022moles equals about a molecular mass of about 42.7 grams.
Work this out exactly. But I wonder what the 500L volume should be, it is not 500L
Answered by
Steph
you were right...the 500L should have been 500ml. Thanks for your help!!!
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