Asked by Help! final next weel
A hydraulic lift in a garage has two pistons: a small one of cross-sectional area 3.70cm2 and a large one of cross-sectional area 210cm2 .
Part A
If this lift is designed to raise a 3100-kg car, what minimum force must be applied to the small piston?
Part B
If the force is applied through compressed air, what must be the minimum air pressure applied to the small piston?
Part A
If this lift is designed to raise a 3100-kg car, what minimum force must be applied to the small piston?
Part B
If the force is applied through compressed air, what must be the minimum air pressure applied to the small piston?
Answers
Answered by
Elena
F₁/A₁=F₂/A₂
F₁=F₂A₁/A₂=mg A₁/A₂=
=3100 •9.8•3.7/210 = 535.3 N
p=F₁/A₁=535.3/3.7•10⁻⁴=1.447•10⁶ Pa
F₁=F₂A₁/A₂=mg A₁/A₂=
=3100 •9.8•3.7/210 = 535.3 N
p=F₁/A₁=535.3/3.7•10⁻⁴=1.447•10⁶ Pa
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