Asked by Radius of a piston
A hydraulic lift has a leak so that it is only 6.0 × 101% efficient in raising its load. If the large piston exerts a force of 1.00 × 102 N when the small piston is depressed with a force of 15 N and the radius of the small piston is 18 cm, what is the radius of the large piston?
Answers
Answered by
bobpursley
pressure on each side is the same.
forcesmall*.60/areasmall= forcelarge/arealarge
15/pi*18^2=100/(pi*rl^2*.6)
solve for rlarge.
forcesmall*.60/areasmall= forcelarge/arealarge
15/pi*18^2=100/(pi*rl^2*.6)
solve for rlarge.
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