Asked by Faidza
Consider a hydraulic lift whose cross-sectional areas A1 and A2 are both circles. If a force F1=125N is required to lift a 1520-kg car, what must be the ratio d2/d1 where d1 and d2 are the diameters of the cross-sectional areas A1 and A2?
Answers
Answered by
Damon
F2/F1 = 1520/125 = Area2/Area1 = pi d2^2/4 / pi d1^2/4
= d2^2/d1^2
d2/d1 = sqrt (F2/F1) = sqrt (1520/125)
= d2^2/d1^2
d2/d1 = sqrt (F2/F1) = sqrt (1520/125)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.