Asked by Faidza
Consider a hydraulic lift whose cross-sectional areas A1 and A2 are both circles. If a force F1=125N is required to lift a 1520-kg car, what must be the ratio d2/d1 where d1 and d2 are the diameters of the cross-sectional areas A1 and A2?
Answers
Answered by
Damon
F2/F1 = 1520/125 = Area2/Area1 = pi d2^2/4 / pi d1^2/4
= d2^2/d1^2
d2/d1 = sqrt (F2/F1) = sqrt (1520/125)
= d2^2/d1^2
d2/d1 = sqrt (F2/F1) = sqrt (1520/125)