Asked by keikei
Write the expression as a single logarithm:
2lnx+3lny-ln2-4lnz
2lnx+3lny-ln2-4lnz
Answers
Answered by
Steve
2lnx+3lny-ln2-4lnz
ln(x^2) + ln(y^3) - ln(2) - ln(z^4)
ln(x^2y^3 / 2z^4)
ln(x^2) + ln(y^3) - ln(2) - ln(z^4)
ln(x^2y^3 / 2z^4)
Answered by
Bosnian
ln ( a ^ n ) = n * ln ( a )
ln ( a ) + ln ( b ) = ln ( a * b )
ln ( a ) - ln ( b ) = ln ( a / b )
2 ln ( x ) + 3 ln ( y ) - ln ( 2 ) - 4 ln ( z ) =
2 ln ( x ) + 3 ln ( y ) - [ ln ( 2 ) + 4 ln ( z ) ] =
ln ( x ^ 2 * y ^ 3) - ln ( 2 z ^ 4 ) =
ln ( x ^ 2 * y ^ 3 / 2 z ^ 4 )
ln ( a ) + ln ( b ) = ln ( a * b )
ln ( a ) - ln ( b ) = ln ( a / b )
2 ln ( x ) + 3 ln ( y ) - ln ( 2 ) - 4 ln ( z ) =
2 ln ( x ) + 3 ln ( y ) - [ ln ( 2 ) + 4 ln ( z ) ] =
ln ( x ^ 2 * y ^ 3) - ln ( 2 z ^ 4 ) =
ln ( x ^ 2 * y ^ 3 / 2 z ^ 4 )
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