since loga - logb = log(a/b), we have
log_3 40-log_3 10
= log_3(40/10)
= log_3(4)
logs are just exponents in reverse. You know that
x^6/x^4 = x^(6-4)
log_3(40) is the power of 3 you need to get 40
since ^ and log are inverse operations,
3^(log_3(x)) = x
log_3(3^x) = x
just as
√x^2 = (√x)^2 = x
(x/2)*2 = (x*2)/2 = x
(x+2)-2 = (x-2)+2 = x
Write the expression as a single logarithm.
log_3 40-log_3 10
I'm completely confused with logarithmic equations!! Can someone please please help me understand?
1 answer
1 answer