Question

A 200g block of copper at 90o
C is dropped into 400g of water at 27o
C contained
in a 300g glass beaker at 27o
C. What is the final equilibrium temperature of the
mixture?
cCu = 0.0924 cal/g°C
cglass = 0.2 cal/g°C
cwater = 1 cal/g°C
The sum of heats gained is zero.

heat gained by copper+heatgainedwater+hatgainedglass=0

mCu*Ccu(Tf-90)+mglass*Cglas*(Tf-27)+mwater*cwat(Tf-27)=0
solve for Tf

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