q = mass Cu x specific heat Cu x (Tfnal-Tinitial)
q = 857 J. Substitute and solve for Tf.
q = 857 J. Substitute and solve for Tf.
The formula for heat transfer is:
Q = mcΔT
Where:
Q = heat transferred (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, you are given:
Q = 857 J
m = 25.0 g
c (specific heat capacity of copper) = 0.39 J/g°C (approximately)
ΔT = final temperature - initial temperature
First, rearrange the formula to solve for ΔT:
Q = mcΔT
ΔT = Q / (mc)
Substitute the given values into the formula:
ΔT = 857 J / (25.0 g * 0.39 J/g°C)
By calculating the numerator and denominator separately:
ΔT = 857 J / 9.75 J/°C
ΔT = 87.95 °C
Now, to find the final temperature, add the change in temperature (ΔT) to the initial temperature (350.0 °C):
Final temperature = 350.0 °C + 87.95 °C
Final temperature = 437.95 °C
Therefore, the final temperature of the block of copper is approximately 437.95 °C.