Asked by k
A block of copper of unknown mass has an initial temperature of 66.7 ∘ C . The copper is immersed in a beaker containing 95.5g of water at 20.6 ∘ C . When the two substances reach thermal equilibrium, the final temperature is 26.0 ∘ C .What is the mass of the copper block?
Answers
Answered by
DrBob222
heat loss by Cu + heat gained by H2O = 0
heat loss by Cu is
[(mass Cu x specific heat Cu x (Tfinal-Tinitial)]
heat gain by H2O is
[mass H2O x specific heat H2O x (Tfinal-Tinitial)]
Add those and set to zero as follows:
[mass Cu x specific heat Cu x (Tfinal-Tintial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0.
You have only one unknown. Substitute the numbers and solve for the one unknown.
Post your work if you get stuck.
heat loss by Cu is
[(mass Cu x specific heat Cu x (Tfinal-Tinitial)]
heat gain by H2O is
[mass H2O x specific heat H2O x (Tfinal-Tinitial)]
Add those and set to zero as follows:
[mass Cu x specific heat Cu x (Tfinal-Tintial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0.
You have only one unknown. Substitute the numbers and solve for the one unknown.
Post your work if you get stuck.
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