Asked by sam

if it takes 31,500 joules of heat to warm 750g of water, what was the temperature change?

My answer:

Q = (M) (DeltaT) (c)
Delta T=Q
Delta T = 31,500J
--------
750gx 1.0cal/gCo

Delta T = 42oC
Answered by Manisha chettri
Good
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