Asked by sam
if it takes 31,500 joules of heat to warm 750g of water, what was the temperature change?
My answer:
Q = (M) (DeltaT) (c)
Delta T=Q
Delta T = 31,500J
--------
750gx 1.0cal/gCo
Delta T = 42oC
My answer:
Q = (M) (DeltaT) (c)
Delta T=Q
Delta T = 31,500J
--------
750gx 1.0cal/gCo
Delta T = 42oC
Answers
Answered by
Manisha chettri
Good
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