Asked by David

it says "how many joules of energy would be required to heat 29.8 grams of carbon from 25.5 C to 79.3 C. (s= .71 Joules / grams times carbon) & the formula is Q= M x C x delta T .
Answered by DrBob222
What's your problem? You have the formula and the numbers. Plug and chug.
Answered by David
How?
Answered by DrBob222
q = ?
m = mass = 29.8 grams
c = specific heat = .71 J/g*C
delta T = 79.3-25.5 = 53.8

q = 29.8 x 0.71 x 53.8 = ? joules.

It would be helpful if you told me why you couldn't do that, please.
Answered by David
So the answer would be 1233.5 joules?
Answered by DrBob222
Not according to my calculator. Did you punch in the right numbers?
Answered by David
Yeah. What did you get?
Answered by David
1138.3004?
Answered by DrBob222
You couldn't have.
29.8 x 0.71 x 53.8 = 1138.3 J. If you typed the problem in right and that's 0.71 the answer should be rounded to 2 s.f. which is 1.1E3 J. If that was really 0.710 then the answer should be rounded to 1.14E3 J.
It still would be helpful to know the real problem here. I hope this isn't a case of just not doing the work and getting someone on line to do it for you.
Answered by DrBob222
1138.3004 is right. Now round it to either two or three s.f. depending upon how many you have in that 0.710 number.
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