Asked by Nadia
The antacid Amphogel contains aluminum hydroxide Al(OH)3. How many milliliters of 6.00M HCl are required to react with 150mL of 1.12M Al(OH)3? Al(OH)3(s) + 3HCl(aq) → AlCl3(aq) + 3H2O(aq)
Help please and thanks in advance
Help please and thanks in advance
Answers
Answered by
DrBob222
This is an example of a simple stoichiometry problem (as opposed to a limiting reagent problem) and all of these are worked alike.
Step 1. Write and balance the equation. You have that.
Step 2. Convert mols Al(OH)3 to mols. mol = M x L. (Note: in cases where grams are given, then mol = grams/molar mass.)
Step 3. Using the coefficients in the balanced equation, convert mols Al(OH)3 to mols HCl.
Step 4. Now convert to L. M HCl = mols HCl/L HCl. You know mols and M, solve for L and convert to mL.
Step 1. Write and balance the equation. You have that.
Step 2. Convert mols Al(OH)3 to mols. mol = M x L. (Note: in cases where grams are given, then mol = grams/molar mass.)
Step 3. Using the coefficients in the balanced equation, convert mols Al(OH)3 to mols HCl.
Step 4. Now convert to L. M HCl = mols HCl/L HCl. You know mols and M, solve for L and convert to mL.
Answered by
Anonymous
56
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