Asked by Anonymous

CaCO3 is used as an antacid. How many mL of a 0.10 M HCl solution would be neutralized by 0.500 g of CaCO3.

Answers

Answered by DrBob222
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2
Convert 0.500 g CaCO3 to moles = grams/molar mass = ?
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